MA8353 TRANSFORMS AND PARTIAL DIFFERENTIAL EQUATIONS notes
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- A Course Material onMA – 6351 TRANSFORMS AND PARTIAL DIFFERENTIAL EQUATIONSByMs. K.SRINIVASANASSISTANT PROFESSORDEPARTMENT OF SCINENCE AND HUMANITIESPRATHYUSHA ENGINEERING COLLEGEDownloaded from: annauniversityedu.blogspot.com
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- MA8353 TRANSFORMS AND PARTIAL DIFFERENTIAL EQUATIONS L T P C 3 1 0 4OBJECTIVES:To introduce Fourier series analysis which is central to many applications in engineering apart from itsuse in solving boundary value problems?To acquaint the student with Fourier transform techniques used in wide variety of situations.To introduce the effective mathematical tools for the solutions of partial differential equationsthat model several physical processes and to develop Z transform techniques for discrete timeSystems.UNIT I PARTIAL DIFFERENTIAL EQUATIONS 9+3Formation of partial differential equations – Singular integrals -- Solutions of standard types of first orderpartial differential equations - Lagrange’s linear equation -- Linear partial differential equations of secondand higher order with constant coefficients of both homogeneous and non-homogeneous types.UNIT II FOURIER SERIES 9+3Dirichlet’s conditions – General Fourier series – Odd and even functions – Half range sine series –Halfrange cosine series – Complex form of Fourier series – Parseval’s identity – Harmonic analysis.UNIT III APPLICATIONS OF PARTIAL DIFFERENTIAL 9+3Classification of PDE – Method of separation of variables - Solutions of one dimensional waveequation – One dimensional equation of heat conduction – Steady state solution of two dimensionalequation of heat conduction (excluding insulated edges).UNIT IV FOURIER TRANSFORMS 9+3Statement of Fourier integral theorem – Fourier transform pair – Fourier sine andcosine transforms – Properties – Transforms of simple functions – Convolution theorem – Parseval’sidentity.UNIT V Z - TRANSFORMS AND DIFFERENCE EQUATIONS 9+3Z- transforms - Elementary properties – Inverse Z - transform (using partial fraction and residues) –Convolution theorem - Formation of difference equations – Solution of difference equations using Z -transform.TOTAL (L:45+T:15): 60 PERIODS.TEXT BOOKS:1. Veerarajan. T., "Transforms and Partial Differential Equations", Tata McGraw Hill Education Pvt.Ltd., New Delhi, Second reprint, 2012.2. Grewal. B.S., "Higher Engineering Mathematics", 42nd Edition, Khanna Publishers, Delhi, 2012.3. Narayanan.S., Manicavachagom Pillay.T.K and Ramanaiah.G "Advanced Mathematics forEngineering Students" Vol. II & III, S.Viswanathan Publishers Pvt. Ltd.1998.REFERENCES:1. Bali.N.P and Manish Goyal, "A Textbook of Engineering Mathematics", 7th Edition, LaxmiPublications Pvt Ltd, 2007.2. Ramana.B.V., "Higher Engineering Mathematics", Tata Mc Graw Hill Publishing Company Limited,NewDelhi, 2008.3. Glyn James, "Advanced Modern Engineering Mathematics", 3rd Edition, Pearson Education, 2007.4. Erwin Kreyszig, "Advanced Engineering Mathematics", 8th Edition, Wiley India, 2007.5. Ray Wylie. C and Barrett.L.C, "Advanced Engineering Mathematics" Tata Mc Graw Hill EducationPvt Ltd, Sixth Edition, New Delhi, 2012.6. Datta.K.B., "Mathematical Methods of Science and Engineering", Cengage Learning India Pvt Ltd,Delhi, 2013.Downloaded from: annauniversityedu.blogspot.com
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- S.NOCONTENTSTOPICSPAGE NOUNIT-I PARTIAL DIFFERENTIAL EQUATIONS1.1INTRODUCTION11.2FORMATION OF PARTIAL DIFFERNTIAL EQUATIONS11.3SOLUTIONS OF PARTIAL DIFFERENTIAL EQUATIONS71.4LAGRANGE’S LINEAR EQUATIONS231.5PARTIAL DIFFERENTIAL EQUATIONS OF HIGHER ORDER WITH CONSTANT29CO-EFFECIENTS1.6NON-HOMOGENOUS LINEAR EQUATIONS36UNIT-II FOURIER SERIES2.1INTRODUCTION422.2PERIODIC FUNCTIONS422.3EVEN AND ODD FUNCTIONS542.4HALF RANGE SERIES612.5PARSEVAL’S THEOREM682.6CHANGE OF INTERVAL692.7HARMONIC ANALYSIS762.8COMPLEX FORM OF FOURIER SERIES802.9SUMMARY83UNIT-III APPLICATIONS OF PARTIAL DIFFERENTILA EQUATIONSINTRODUCTION 87SOLUTION OF WAVE EQUATION 87SOLUTION OF THE HEAT EQUATION 105SOLUTION OF LAPLACE EQUATIONS 120UNIT-IV FOURIER TRANSFORMS4.1 INTRODUCTION1334.2 INTEGRAL TRANSFORMS1334.3 FOURIER INTEGRAL THEOREM1344.4 FOURIER TRANSFORMS AND ITS PROPERTIES1374.5 CONVOLUTION THEOREM AND PARSEVAL’S THEOREM1494.6 FOURIER SINE AND COSINE TRANSFORMS154UNIT-V Z-TRANSFORMS AND DIFFERENCE EQUATIONSINTRODUCTION 166LINEAR DIFFERENCE EQUATIONS 167Z-TRANSFORMS AND ITS PROPERTIES 168INVERSE Z-TRANSFORMS 183CONVOLUTION THEOREM 191APPLICATIONS OF Z-TRANSFORMS TO DIFFERENCE EQUATIONS 193FORMATION OF DIFFERENCE EQUATIONS 199BIBLIOGRAPHY 200Downloaded from: annauniversityedu.blogspot.com
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- UNIT– IPARTIAL DIFFERENTIAL EQUATIONSThis unit covers topics that explain the formation of partial differential equationsand the solutions of special types of partial differential equations.INTRODUCTIONA partial differential equation is one which involves one or more partialderivatives. The order of the highest derivative is called the order of the equation. Apartial differential equation contains more than one independent variable. But, here weshall consider partial differential equations involving one dependent variable „z‟ and onlytwo independent variables x and y so that z = f(x,y). We shall denotez z 2z 2z 2z------- = p, ----------- = q, ---------- = r, ---------- = s, ------------ = t.x y x2xy y2A partial differential equation is linear if it is of the first degree in the dependentvariable and its partial derivatives. If each term of such an equation contains either thedependent variable or one of its derivatives, the equation is said to be homogeneous,otherwise it is non homogeneous.Formation of Partial Differential EquationsPartial differential equations can be obtained by the elimination of arbitrary constants orby the elimination of arbitrary functions.By the elimination of arbitrary constantsLet us consider the function ( x, y, z, a, b ) = 0 -------------- (1)where a & b are arbitrary constantsDifferentiating equation (1) partially w.r.t x & y, we get∂ ∂+ p = 0 (2)∂x ∂z∂ ∂+ q = 0 (3)∂y ∂zEliminating a and b from equations (1), (2) and (3), we get a partial differentialequation of the first order of the form f (x,y,z, p, q) = 0Downloaded from: annauniversityedu.blogspot.com
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- Example 1Eliminate the arbitrary constants a & b from z = ax + by + abConsider z = ax + by + ab (1)Differentiating (1) partially w.r.t x & y, we get∂z= a i.e, p= a (2)∂x∂z= b i.e, q = b∂y(3)Using (2) & (3) in (1), we getz = px +qy+ pqwhich is the required partial differential equation.Example 2Form the partial differential equation by eliminating the arbitrary constants a and bfromz = ( x2+a2) ( y2+ b2)Given z = ( x2+a2) ( y2+ b2) (1)Differentiating (1) partially w.r.t x & y , we getp = 2x (y2+ b2)q = 2y (x + a )Substituting the values of p and q in (1), we get4xyz = pqwhich is the required partial differential equation.Downloaded from: annauniversityedu.blogspot.com
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- Example 3Find the partial differential equation of the family of spheres of radius one whose centrelie in the xy - plane.The equation of the sphere is given by( x – a )2+ ( y- b)2+ z2= 1 (1)Differentiating (1) partially w.r.t x & y , we get2 (x-a ) + 2 zp = 02 ( y-b ) + 2 zq = 0From these equations we obtainx-a = -zp (2)y -b = -zq (3)Using (2) and (3) in (1), we getz2p2+ z2q2+ z2= 1or z2( p2+ q2+ 1) = 1Example 4Eliminate the arbitrary constants a, b & c fromx2y2z2+ + = 1 and form the partial differential equation.a2b2c2The given equation isx2y2z2+ + = 1 (1)a2b2c2Downloaded from: annauniversityedu.blogspot.com
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- Differentiating (1) partially w.r.t x & y, we get2x 2zp+ = 0a2c22y 2zq+ = 0b2c2Therefore we getx zp+ = 0 (2)a2c2y zq+ = 0 (3)b2c2Again differentiating (2) partially w.r.t „x‟, we set(1/a2) + (1/ c2) ( zr + p2) = 0 (4)Multiplying ( 4) by x, we getx xz r p2x+ + = 0a2c2c2From (2) , we havezp xzr p2x+ + = 0c2c2c2or -zp + xzr + p2x = 0By the elimination of arbitrary functionsLet u and v be any two functions of x, y, z and Φ(u, v ) = 0, where Φ is anarbitrary function. This relation can be expressed asu = f(v) (1)Downloaded from: annauniversityedu.blogspot.com
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- Differentiating (1) partially w.r.t x & y and eliminating the arbitraryfunctions from these relations, we get a partial differential equation of the first orderof the formf(x, y, z, p, q ) = 0.Example 5Obtain the partial differential equation by eliminating „f „ from z = ( x+y ) f ( x2- y2)Let us now consider the equationz = (x+y ) f(x2- y2) (1)Differentiating (1) partially w.r.t x & y , we getp = ( x + y ) f ' ( x2- y2) . 2x + f ( x2- y2)q = ( x + y ) f ' ( x2- y2) . (-2y) + f ( x2- y2)These equations can be written asp - f ( x2- y2) = ( x + y ) f '( x2- y2) . 2x (2)q - f ( x2- y2) = ( x + y ) f '( x2- y2) .(-2y) (3)Hence, we getp - f ( x2- y2) x= -q - f ( x2- y2) yi.e, py - yf( x2- y2) = -qx +xf ( x2- y2)i.e, py +qx = ( x+y ) f ( x2- y2)Therefore, we have by(1), py +qx = zExample 6Form the partial differential equation by eliminating the arbitrary function ffromz = eyf (x + y)Consider z = eyf ( x +y ) ( 1)Differentiating (1) partially w .r. t x & y, we getp = eyf ' (x + y)q = eyf '(x + y) + f(x + y). eyHence, we haveq = p + zDownloaded from: annauniversityedu.blogspot.com
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- Example 7Form the PDE by eliminating f & Φ from z = f (x +ay ) + Φ ( x – ay)Consider z = f (x +ay ) + Φ ( x – ay) (1)Differentiating (1) partially w.r.t x &y , we getp = f '(x +ay ) + Φ' (x – ay) (2)q = f ' (x +ay ) .a + Φ' (x – ay) ( -a) (3)Differentiating (2) & (3) again partially w.r.t x & y, we getr = f "( x+ay) + Φ "( x – ay)t = f "( x+ay) .a2+ Φ"( x – ay) (-a)2i.e, t = a2{ f"( x + ay) + Φ"( x – ay)}or t = a2rExercises:1.Form the partial differential equation by eliminating the arbitrary constants „a‟ &„b‟ from the following equations.(i)z = ax + by(ii)x2+ y2z2+ = 1a2b2(iii)z = ax + by + a2+ b2(iv)ax2+ by2+ cz2= 1(v)z = a2x + b2y + ab2.Find the PDE of the family of spheres of radius 1 having their centres lie on thexy plane{Hint: (x – a)2+ (y – b)2+ z2= 1}3.Find the PDE of all spheres whose centre lie on the (i) z axis (ii) x-axis4.Form the partial differential equations by eliminating the arbitrary functions in thefollowing cases.(i)z = f (x + y)(ii)z = f (x2– y2)(iii)z = f (x2+ y2+ z2)(iv) (xyz, x + y + z) = 0Downloaded from: annauniversityedu.blogspot.com
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- (v)z = x + y + f(xy)(vi)z = xy + f (x2+ y2)(vii)z = f xyz(viii)F (xy + z2, x + y + z) = 0(ix)z = f (x + iy) +f (x – iy)(x) z = f(x3+ 2y) +g(x3– 2y)SOLUTIONS OF A PARTIAL DIFFERENTIAL EQUATIONA solution or integral of a partial differential equation is a relation connecting thedependent and the independent variables which satisfies the given differential equation. Apartial differential equation can result both from elimination of arbitrary constants andfrom elimination of arbitrary functions as explained in section 1.2. But, there is a basicdifference in the two forms of solutions. A solution containing as many arbitraryconstants as there are independent variables is called a complete integral. Here, the partialdifferential equations contain only two independent variables so that the completeintegral will include two constants.A solution obtained by giving particular values to thearbitrary constants in a complete integral is called a particular integral.Singular IntegralLet f (x,y,z,p,q) = 0 ----------- (1)be the partial differential equation whose complete integral is (x,y,z,a,b) = 0 --------------- (2)where „a‟ and „b‟ are arbitrary constants.Differentiating (2) partially w.r.t. a and b, we obtain-------- = 0 ----------- (3)aand --------- = 0 -------------------------------------- (4)bThe eliminant of „a‟ and „b‟ from the equations (2), (3) and (4), when it exists, iscalled the singular integral of (1).Downloaded from: annauniversityedu.blogspot.com
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