MA8353 TRANSFORMS AND PARTIAL DIFFERENTIAL EQUATIONS notes

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  • A Course Material on
    MA 6351 TRANSFORMS AND PARTIAL DIFFERENTIAL EQUATIONS
    By
    Ms. K.SRINIVASAN
    ASSISTANT PROFESSOR
    DEPARTMENT OF SCINENCE AND HUMANITIES
    PRATHYUSHA ENGINEERING COLLEGE
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  • MA8353 TRANSFORMS AND PARTIAL DIFFERENTIAL EQUATIONS L T P C 3 1 0 4
    OBJECTIVES:
    To introduce Fourier series analysis which is central to many applications in engineering apart from its
    use in solving boundary value problems?
    To acquaint the student with Fourier transform techniques used in wide variety of situations.
    To introduce the effective mathematical tools for the solutions of partial differential equations
    that model several physical processes and to develop Z transform techniques for discrete time
    Systems.
    UNIT I PARTIAL DIFFERENTIAL EQUATIONS 9+3
    Formation of partial differential equations Singular integrals -- Solutions of standard types of first order
    partial differential equations - Lagrange’s linear equation -- Linear partial differential equations of second
    and higher order with constant coefficients of both homogeneous and non-homogeneous types.
    UNIT II FOURIER SERIES 9+3
    Dirichlet’s conditions – General Fourier series Odd and even functions Half range sine series Half
    range cosine series Complex form of Fourier series Parseval’s identity Harmonic analysis.
    UNIT III APPLICATIONS OF PARTIAL DIFFERENTIAL 9+3
    Classification of PDE Method of separation of variables - Solutions of one dimensional wave
    equation One dimensional equation of heat conduction Steady state solution of two dimensional
    equation of heat conduction (excluding insulated edges).
    UNIT IV FOURIER TRANSFORMS 9+3
    Statement of Fourier integral theorem Fourier transform pair Fourier sine and
    cosine transforms Properties Transforms of simple functions Convolution theorem Parseval’s
    identity.
    UNIT V Z - TRANSFORMS AND DIFFERENCE EQUATIONS 9+3
    Z- transforms - Elementary properties Inverse Z - transform (using partial fraction and residues)
    Convolution theorem - Formation of difference equations Solution of difference equations using Z -
    transform.
    TOTAL (L:45+T:15): 60 PERIODS.
    TEXT BOOKS:
    1. Veerarajan. T., "Transforms and Partial Differential Equations", Tata McGraw Hill Education Pvt.
    Ltd., New Delhi, Second reprint, 2012.
    2. Grewal. B.S., "Higher Engineering Mathematics", 42nd Edition, Khanna Publishers, Delhi, 2012.
    3. Narayanan.S., Manicavachagom Pillay.T.K and Ramanaiah.G "Advanced Mathematics for
    Engineering Students" Vol. II & III, S.Viswanathan Publishers Pvt. Ltd.1998.
    REFERENCES:
    1. Bali.N.P and Manish Goyal, "A Textbook of Engineering Mathematics", 7th Edition, Laxmi
    Publications Pvt Ltd, 2007.
    2. Ramana.B.V., "Higher Engineering Mathematics", Tata Mc Graw Hill Publishing Company Limited,
    NewDelhi, 2008.
    3. Glyn James, "Advanced Modern Engineering Mathematics", 3rd Edition, Pearson Education, 2007.
    4. Erwin Kreyszig, "Advanced Engineering Mathematics", 8th Edition, Wiley India, 2007.
    5. Ray Wylie. C and Barrett.L.C, "Advanced Engineering Mathematics" Tata Mc Graw Hill Education
    Pvt Ltd, Sixth Edition, New Delhi, 2012.
    6. Datta.K.B., "Mathematical Methods of Science and Engineering", Cengage Learning India Pvt Ltd,
    Delhi, 2013.
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  • S.NO
    CONTENTS
    TOPICS
    PAGE NO
    UNIT-I PARTIAL DIFFERENTIAL EQUATIONS
    1.1
    INTRODUCTION
    1
    1.2
    FORMATION OF PARTIAL DIFFERNTIAL EQUATIONS
    1
    1.3
    SOLUTIONS OF PARTIAL DIFFERENTIAL EQUATIONS
    7
    1.4
    LAGRANGE’S LINEAR EQUATIONS
    23
    1.5
    PARTIAL DIFFERENTIAL EQUATIONS OF HIGHER ORDER WITH CONSTANT
    29
    CO-EFFECIENTS
    1.6
    NON-HOMOGENOUS LINEAR EQUATIONS
    36
    UNIT-II FOURIER SERIES
    2.1
    INTRODUCTION
    42
    2.2
    PERIODIC FUNCTIONS
    42
    2.3
    EVEN AND ODD FUNCTIONS
    54
    2.4
    HALF RANGE SERIES
    61
    2.5
    PARSEVAL’S THEOREM
    68
    2.6
    CHANGE OF INTERVAL
    69
    2.7
    HARMONIC ANALYSIS
    76
    2.8
    COMPLEX FORM OF FOURIER SERIES
    80
    2.9
    SUMMARY
    83
    UNIT-III APPLICATIONS OF PARTIAL DIFFERENTILA EQUATIONS
    INTRODUCTION 87
    SOLUTION OF WAVE EQUATION 87
    SOLUTION OF THE HEAT EQUATION 105
    SOLUTION OF LAPLACE EQUATIONS 120
    UNIT-IV FOURIER TRANSFORMS
    4.1 INTRODUCTION
    133
    4.2 INTEGRAL TRANSFORMS
    133
    4.3 FOURIER INTEGRAL THEOREM
    134
    4.4 FOURIER TRANSFORMS AND ITS PROPERTIES
    137
    4.5 CONVOLUTION THEOREM AND PARSEVAL’S THEOREM
    149
    4.6 FOURIER SINE AND COSINE TRANSFORMS
    154
    UNIT-V Z-TRANSFORMS AND DIFFERENCE EQUATIONS
    INTRODUCTION 166
    LINEAR DIFFERENCE EQUATIONS 167
    Z-TRANSFORMS AND ITS PROPERTIES 168
    INVERSE Z-TRANSFORMS 183
    CONVOLUTION THEOREM 191
    APPLICATIONS OF Z-TRANSFORMS TO DIFFERENCE EQUATIONS 193
    FORMATION OF DIFFERENCE EQUATIONS 199
    BIBLIOGRAPHY 200
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  • UNIT I
    PARTIAL DIFFERENTIAL EQUATIONS
    This unit covers topics that explain the formation of partial differential equations
    and the solutions of special types of partial differential equations.
    INTRODUCTION
    A partial differential equation is one which involves one or more partial
    derivatives. The order of the highest derivative is called the order of the equation. A
    partial differential equation contains more than one independent variable. But, here we
    shall consider partial differential equations involving one dependent variable „z‟ and only
    two independent variables x and y so that z = f(x,y). We shall denote
    z z
    2
    z
    2
    z
    2
    z
    ------- = p, ----------- = q, ---------- = r, ---------- = s, ------------ = t.
    x y x
    2
    xy y
    2
    A partial differential equation is linear if it is of the first degree in the dependent
    variable and its partial derivatives. If each term of such an equation contains either the
    dependent variable or one of its derivatives, the equation is said to be homogeneous,
    otherwise it is non homogeneous.
    Formation of Partial Differential Equations
    Partial differential equations can be obtained by the elimination of arbitrary constants or
    by the elimination of arbitrary functions.
    By the elimination of arbitrary constants
    Let us consider the function
    ( x, y, z, a, b ) = 0 -------------- (1)
    where a & b are arbitrary constants
    Differentiating equation (1) partially w.r.t x & y, we get
    
    + p = 0 (2)
    ∂x ∂z
    
    + q = 0 (3)
    ∂y ∂z
    Eliminating a and b from equations (1), (2) and (3), we get a partial differential
    equation of the first order of the form f (x,y,z, p, q) = 0
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  • Example 1
    Eliminate the arbitrary constants a & b from z = ax + by + ab
    Consider z = ax + by + ab (1)
    Differentiating (1) partially w.r.t x & y, we get
    ∂z
    = a i.e, p= a (2)
    ∂x
    ∂z
    = b i.e, q = b
    ∂y
    (3)
    Using (2) & (3) in (1), we get
    z = px +qy+ pq
    which is the required partial differential equation.
    Example 2
    Form the partial differential equation by eliminating the arbitrary constants a and b
    from
    z = ( x
    2
    +a
    2
    ) ( y
    2
    + b
    2
    )
    Given z = ( x
    2
    +a
    2
    ) ( y
    2
    + b
    2
    ) (1)
    Differentiating (1) partially w.r.t x & y , we get
    p = 2x (y
    2
    + b
    2
    )
    q = 2y (x + a )
    Substituting the values of p and q in (1), we get
    4xyz = pq
    which is the required partial differential equation.
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  • Example 3
    Find the partial differential equation of the family of spheres of radius one whose centre
    lie in the xy - plane.
    The equation of the sphere is given by
    ( x a )
    2
    + ( y- b)
    2
    + z
    2
    = 1 (1)
    Differentiating (1) partially w.r.t x & y , we get
    2 (x-a ) + 2 zp = 0
    2 ( y-b ) + 2 zq = 0
    From these equations we obtain
    x-a = -zp (2)
    y -b = -zq (3)
    Using (2) and (3) in (1), we get
    z
    2
    p
    2
    + z
    2
    q
    2
    + z
    2
    = 1
    or z
    2
    ( p
    2
    + q
    2
    + 1) = 1
    Example 4
    Eliminate the arbitrary constants a, b & c from
    x
    2
    y
    2
    z
    2
    + + = 1 and form the partial differential equation.
    a
    2
    b
    2
    c
    2
    The given equation is
    x
    2
    y
    2
    z
    2
    + + = 1 (1)
    a
    2
    b
    2
    c
    2
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  • Differentiating (1) partially w.r.t x & y, we get
    2x 2zp
    + = 0
    a
    2
    c
    2
    2y 2zq
    + = 0
    b
    2
    c
    2
    Therefore we get
    x zp
    + = 0 (2)
    a
    2
    c
    2
    y zq
    + = 0 (3)
    b
    2
    c
    2
    Again differentiating (2) partially w.r.t „x‟, we set
    (1/a
    2
    ) + (1/ c
    2
    ) ( zr + p
    2
    ) = 0 (4)
    Multiplying ( 4) by x, we get
    x xz r p
    2
    x
    + + = 0
    a
    2
    c
    2
    c
    2
    From (2) , we have
    zp xzr p
    2
    x
    + + = 0
    c
    2
    c
    2
    c
    2
    or -zp + xzr + p
    2
    x = 0
    By the elimination of arbitrary functions
    Let u and v be any two functions of x, y, z and Φ(u, v ) = 0, where Φ is an
    arbitrary function. This relation can be expressed as
    u = f(v) (1)
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  • Differentiating (1) partially w.r.t x & y and eliminating the arbitrary
    functions from these relations, we get a partial differential equation of the first order
    of the form
    f(x, y, z, p, q ) = 0.
    Example 5
    Obtain the partial differential equation by eliminating „f „ from z = ( x+y ) f ( x
    2
    - y
    2
    )
    Let us now consider the equation
    z = (x+y ) f(x
    2
    - y
    2
    ) (1)
    Differentiating (1) partially w.r.t x & y , we get
    p = ( x + y ) f ' ( x
    2
    - y
    2
    ) . 2x + f ( x
    2
    - y
    2
    )
    q = ( x + y ) f ' ( x
    2
    - y
    2
    ) . (-2y) + f ( x
    2
    - y
    2
    )
    These equations can be written as
    p - f ( x
    2
    - y
    2
    ) = ( x + y ) f '( x
    2
    - y
    2
    ) . 2x (2)
    q - f ( x
    2
    - y
    2
    ) = ( x + y ) f '( x
    2
    - y
    2
    ) .(-2y) (3)
    Hence, we get
    p - f ( x
    2
    - y
    2
    ) x
    = -
    q - f ( x
    2
    - y
    2
    ) y
    i.e, py - yf( x
    2
    - y
    2
    ) = -qx +xf ( x
    2
    - y
    2
    )
    i.e, py +qx = ( x+y ) f ( x
    2
    - y
    2
    )
    Therefore, we have by(1), py +qx = z
    Example 6
    Form the partial differential equation by eliminating the arbitrary function f
    from
    z = e
    y
    f (x + y)
    Consider z = e
    y
    f ( x +y ) ( 1)
    Differentiating (1) partially w .r. t x & y, we get
    p = e
    y
    f ' (x + y)
    q = e
    y
    f '(x + y) + f(x + y). e
    y
    Hence, we have
    q = p + z
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  • Example 7
    Form the PDE by eliminating f & Φ from z = f (x +ay ) + Φ ( x – ay)
    Consider z = f (x +ay ) + Φ ( x ay) (1)
    Differentiating (1) partially w.r.t x &y , we get
    p = f '(x +ay ) + Φ' (x ay) (2)
    q = f ' (x +ay ) .a + Φ' (x – ay) ( -a) (3)
    Differentiating (2) & (3) again partially w.r.t x & y, we get
    r = f "( x+ay) + Φ "( x – ay)
    t = f "( x+ay) .a
    2
    + Φ"( x – ay) (-a)
    2
    i.e, t = a
    2
    { f"( x + ay) + Φ"( x – ay)}
    or t = a
    2
    r
    Exercises:
    1.
    Form the partial differential equation by eliminating the arbitrary constants „a‟ &
    „b‟ from the following equations.
    (i)
    z = ax + by
    (ii)
    x
    2
    + y
    2
    z
    2
    + = 1
    a
    2
    b
    2
    (iii)
    z = ax + by + a
    2
    + b
    2
    (iv)
    ax
    2
    + by
    2
    + cz
    2
    = 1
    (v)
    z = a
    2
    x + b
    2
    y + ab
    2.
    Find the PDE of the family of spheres of radius 1 having their centres lie on the
    xy plane{Hint: (x a)
    2
    + (y b)
    2
    + z
    2
    = 1}
    3.
    Find the PDE of all spheres whose centre lie on the (i) z axis (ii) x-axis
    4.
    Form the partial differential equations by eliminating the arbitrary functions in the
    following cases.
    (i)
    z = f (x + y)
    (ii)
    z = f (x
    2
    y
    2
    )
    (iii)
    z = f (x
    2
    + y
    2
    + z
    2
    )
    (iv)
    (xyz, x + y + z) = 0
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  • (v)
    z = x + y + f(xy)
    (vi)
    z = xy + f (x
    2
    + y
    2
    )
    (vii)
    z = f xy
    z
    (viii)
    F (xy + z
    2
    , x + y + z) = 0
    (ix)
    z = f (x + iy) +f (x iy)
    (x) z = f(x
    3
    + 2y) +g(x
    3
    2y)
    SOLUTIONS OF A PARTIAL DIFFERENTIAL EQUATION
    A solution or integral of a partial differential equation is a relation connecting the
    dependent and the independent variables which satisfies the given differential equation. A
    partial differential equation can result both from elimination of arbitrary constants and
    from elimination of arbitrary functions as explained in section 1.2. But, there is a basic
    difference in the two forms of solutions. A solution containing as many arbitrary
    constants as there are independent variables is called a complete integral. Here, the partial
    differential equations contain only two independent variables so that the complete
    integral will include two constants.A solution obtained by giving particular values to the
    arbitrary constants in a complete integral is called a particular integral.
    Singular Integral
    Let f (x,y,z,p,q) = 0 ----------- (1)
    be the partial differential equation whose complete integral is
    (x,y,z,a,b) = 0 --------------- (2)
    where „a‟ and „b‟ are arbitrary constants.
    Differentiating (2) partially w.r.t. a and b, we obtain
    
    -------- = 0 ----------- (3)
    a
    
    and --------- = 0 -------------------------------------- (4)
    b
    The eliminant of „a‟ and „b‟ from the equations (2), (3) and (4), when it exists, is
    called the singular integral of (1).
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